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NEW QUESTION: 1
In which key areas can we expect there to be improvements when running SAP BW on SAP HANA?
There are 2 correct answers to this question.
Response:
A. Data loading performance
B. Reporting performance
C. Superior data quality
D. Tighter security
Answer: A,B

NEW QUESTION: 2
Which of the following is a mandatory sub-element of the <web-resource-collection> element of the deployment descriptor?
A. <http-method>
B. <url-pattern>
C. <description>
D. <web-resource-name>
Answer: D

NEW QUESTION: 3
The RSA Algorithm uses which mathematical concept as the basis of its encryption?
A. Geometry
B. PI (3.14159...)
C. 16-round ciphers
D. Two large prime numbers
Answer: D
Explanation:
Source: TIPTON, et. al, Official (ISC)2 Guide to the CISSP CBK, 2007 edition, page 254.
And from the RSA web site, http://www.rsa.com/rsalabs/node.asp?id=2214 :
The RSA cryptosystem is a public-key cryptosystem that offers both encryption and digital signatures (authentication). Ronald Rivest, Adi Shamir, and Leonard Adleman developed the RSA system in 1977 [RSA78]; RSA stands for the first letter in each of its inventors' last names.
The RSA algorithm works as follows: take two large primes, p and q, and compute their product n = pq; n is called the modulus. Choose a number, e, less than n and relatively prime to (p-1)(q-1), which means e and (p-1)(q-1) have no common factors except 1. Find another number d such that (ed - 1) is divisible by (p-1)(q-1). The values e and d are called the public and private exponents, respectively. The public key is the pair (n, e); the private key is (n, d). The factors p and q may be destroyed or kept with the private key.
It is currently difficult to obtain the private key d from the public key (n, e). However if one could factor n into p and q, then one could obtain the private key d. Thus the security of the
RSA system is based on the assumption that factoring is difficult. The discovery of an easy method of factoring would "break" RSA (see Question 3.1.3 and Question 2.3.3).
Here is how the RSA system can be used for encryption and digital signatures (in practice, the actual use is slightly different; see Questions 3.1.7 and 3.1.8):
Encryption
Suppose Alice wants to send a message m to Bob. Alice creates the ciphertext c by exponentiating: c = me mod n, where e and n are Bob's public key. She sends c to Bob. To decrypt, Bob also exponentiates: m = cd mod n; the relationship between e and d ensures that Bob correctly recovers m. Since only Bob knows d, only Bob can decrypt this message.
Digital Signature
Suppose Alice wants to send a message m to Bob in such a way that Bob is assured the message is both authentic, has not been tampered with, and from Alice. Alice creates a digital signature s by exponentiating: s = md mod n, where d and n are Alice's private key.
She sends m and s to Bob. To verify the signature, Bob exponentiates and checks that the message m is recovered: m = se mod n, where e and n are Alice's public key.
Thus encryption and authentication take place without any sharing of private keys: each person uses only another's public key or their own private key. Anyone can send an encrypted message or verify a signed message, but only someone in possession of the correct private key can decrypt or sign a message.

NEW QUESTION: 4
ニーズの評価を実行した後、トレーナーは、聴衆のスキルと才能が組織が要求しているトレーニングと一致しないと判断します。聴衆のスキルレベルは不十分であり、組織が提案するカリキュラムを進めることはできません。次のうち、トレーナーにとって最適なアプローチはどれですか？
A. トレーニングを開始し、講義中のスキル不足を補うようにします。
B. 元のコース設計を無視してトレーニングを開始し、現在必要なスキルについてトレーニングします。
C. 最も有能な個人と協力し、他の人を支援するよう依頼します。
D. 調査結果を組織に報告し、別のトレーニング戦略を提案します。
Answer: D