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NEW QUESTION: 1
Refer to the exhibit.
Which additional configuration is necessary for R1 and R2 to become OSPF neighbors?
A. R1
!
interface FastEthernet0/0
ip ospf mtu-ignore
!
R2
!
interface FastEthernet0/1
ip ospf mtu-ignore
!
B. R2
!
router ospf 10
no network 10.1.1.6 0.0.0.0 area 0
network 10.1.1.6 0.0.0.0 area 1
!
C. R1
!
router ospf 1
no passive-interface Fastethernet0/0
!
D. R1
!
no router ospf 1
router ospf 10
network 10.1.1.5 0.0.0.0 area 0
Answer: C
Explanation:
Explanation/Reference:
Explanation:
Because the passive interface default command is used, by default all interfaces are passive and no neighbors will form on these interfaces. We need to disable passive interface on the link to R2 by using the
"
no passive-interface Fastethernet0/0" on R1 under OSPF.

NEW QUESTION: 2
You are administering a database that supports an OLTP workload. CURSOR_SHARINGis set to EXACTfor the instance. An application is frequently executing almost identical queries that vary in literal values in the WHEREclause, causing a large number of hard parses to occur.
Which four statements would be true if you use bind variables for these queries? (Choose four.)
A. Mutex contention in the library cache will be reduced.
B. The optimizer will generate the same plan for all bind values if no histograms exist on the columns used in the WHEREclause of these queries.
C. The optimizer will use bind peeking and use the literal value to determine the execution plan for these queries.
D. Hard parses will be reduced for the queries.
E. The optimizer will use bind peeking and subsequent execution of the queries will always generate the same plans irrespective of the cardinality.
F. The optimizer will use one parent cursor and one child cursor for each SQL statement with different literal values.
Answer: A,D,E,F

NEW QUESTION: 3
Given:
11.public class Person {
12.private name;
13.public Person(String name) {
14.this.name = name;
15.}
16.public int hashCode() {
17.return 420;
18.}
19.}
Which statement is true?
A. The time to determine whether a Person object is contained in a HashSet is constant and does NOT depend on the size of the map.
B. Deleting a Person key from a HashMap will delete all map entries for all keys of type Person.
C. Inserting a second Person object into a HashSet will cause the first Person object to be removed as a duplicate.
D. The time to find the value from HashMap with a Person key depends on the size of the map.
Answer: D