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NEW QUESTION: 1
Which two statements are true about unicast RPF? (Choose two.)
A. CEF is optional with Unicast RPF, but when CEF is enabled it provides better performance.
B. Unicast RPF requires CEF to be enabled.
C. Unicast RPF strict mode works better with multihomed networks.
D. Unicast RPF strict mode supports symmetric paths.
E. Unicast RPF strict mode supports asymmetric paths.
Answer: B,D
Explanation:
Explanation/Reference:
Explanation:
Unicast RPF requires Cisco express forwarding (CEF) to function properly on the router.
Strict Versus Loose Checking Mode
The Unicast RPF in Strict Mode feature filters ingress IPv4 traffic in strict checking mode and forwards packets only if the following conditions are satisfied.
An IPv4 packet must be received at an interface with the best return path (route) to the packet source (a process called symmetric routing). There must be a route in the Forwarding Information Base (FIB) that matches the route to the receiving interface. Adding a route in the FIB can be done via static route, network statement, or dynamic routing.
IPv4 source addresses at the receiving interface must match the routing entry for the interface.
References:
http://www.cisco.com/c/en/us/td/docs/ios/12_2/security/configuration/guide/fsecur_c/scfrpf.html
http://www.cisco.com/c/en/us/td/docs/ios/12_0s/feature/guide/srpf_gsr.html

NEW QUESTION: 2
与えられた：
class Student {
String course, name, city;
public Student (String name, String course, String city) {
this.course = course; this.name = name; this.city = city;
}
public String toString() {
return course + ":" + name + ":" + city;
}
public String getCourse() {return course;}
public String getName() {return name;}
public String getCity() {return city;}
and the code fragment:
List<Student> stds = Arrays.asList(
new Student ("Jessy", "Java ME", "Chicago"),
new Student ("Helen", "Java EE", "Houston"),
new Student ("Mark", "Java ME", "Chicago"));
stds.stream()
.collect(Collectors.groupingBy(Student::getCourse))
.forEach(src, res) -> System.out.println(res));
結果は何ですか？
A. Java EEJava ME
B. A compilation error occurs.
C. [Java EE: Helen:Houston][Java ME: Jessy:Chicago, Java ME: Mark:Chicago]
D. [Java ME: Jessy:Chicago, Java ME: Mark:Chicago][Java EE: Helen:Houston]
Answer: A

NEW QUESTION: 3
エンジニアは、会社のCisco Wireless LAN Controllerのデータリンク冗長性を作成する必要があります。エンジニアは、ポートベースの冗長性ではなく、LAGベースの冗長性を構成することを決定しました。 LAGベースの冗長性のどの3つの機能がこの決定に影響を与えましたか？ （3つ選択してください。）
A. 2つの個別の非スタックスイッチへのインターフェイス接続が利用可能です。
B. ポートは複数のLAGにグループ化されます。
C. パケットは常に、受信したポートと同じポートに送信されます。
D. 1つのポートが稼働している限り、すべてのインターフェーストラフィックが通過します。
E. 同じポートに複数のタグなしダイナミックインターフェイスがあります。
F. すべてのリンクの全帯域幅が利用可能です。
Answer: B,C,D
Explanation:
https://community.cisco.com/t5/wireless-mobility-documents/lag-link-aggregation/ta-p/3128669