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NEW QUESTION: 1
SIMULATION


Answer:
Explanation:
The question mentioned Boston router was not configured correctly or incomplete so we should check this router
first. Click on Host B to access the command line interface (CLI) of Boston router.
Explanation:
Boston>enable (type cisco as its password here)
Boston#show running-config

First, remember that the current OSPF Process ID is 2 because we will need it for later configuration. Next notice that
in the second "network" command the network and wildcard mask are 192.168.155.0 and 0.0.0.3 which is equivalent
to 192.168.155.0 255.255.255.252 in term of subnet mask. Therefore this subnetwork's range is from 192.168.155.0
to 192.168.155.3 but the ip address of s0/0 interface of Boston router is 192.168.155.5 which don't belong to this
range -> this is the reason why OSPF did not recognize s0 interface of Boston router as a part of area 0. So we need to
find a subnetwork that s0 interface belongs to.
IP address of S0 interface: 192.168.155.5/30
Subnet mask: /30 = 1111 1111.1111 1111.1111 1111.1111 1100
Increment: 4
Network address (which IP address of s0 interface belongs to): 192.168.155.4 (because 4 * 1 = 4 < 5)
Therefore we must use this network instead of 192.168.155.0 network
Boston#configure terminal
Boston(config)#router ospf 2
Boston(config-router)#no network 192.168.155.0 0.0.0.3 area 0
Boston(config-router)#network 192.168.155.4 0.0.0.3 area 0
Boston(config-router)#end
Boston#copy running-config startup-config
Finally, you should issue a ping command from Boston router to Lancaster router to make sure it works well.
Boston#ping 192.168.43.1

NEW QUESTION: 2
Which data protection benefit does Symmetrix Service Credential provide?
A. Provides service connection encryption
B. Maintains protection during maintenance operations
C. Maintains SRDF data-in-flight protection
D. Provides user host connection authentication
Answer: B

NEW QUESTION: 3
Refer to the exhibit. What type of attack is represented in the given Wireshark packet capture?

A. a shrew attack
B. spoofing
C. a duplicate ACK
D. TCP congestion control
E. a SYN flood
Answer: E