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NEW QUESTION: 1
Which transaction do you use to access the general Customizing activities for Access
Control?
A. Call View Maintenance (SM30)
B. Launchpad Customizing (LPD_CUST)
C. MSMP Workflow Configuration (GRFNMW_CONFIGURE)
D. Customizing - Edit Project (SPRO)
Answer: D
NEW QUESTION: 2
You manage a SQL Server 2008 instance.
You need to verify whether a database integrity check (DBCC CHECKDB) was run for a particular database.
Which log file should you examine?
A. ERRORLOG
B. default.trc
C. log.trc
D. SQLAGENT
Answer: A
NEW QUESTION: 3
A production SQL Server Analysis Services (SSAS) cube is processed daily. The users query facts by using a hierarchy named Geography from a dimension named Geography.
The DimGeography table in the data source view is used as the source of the Geography dimension. The table has the following structure.
The Geography dimension has three attribute hierarchies:
City
State-Province
Country
The attributes have the following relationships defined: City> State-Province > Country. Each attribute has a key and a name sourced from the related key and name columns in the DimGeography table.
During processing, you receive the following error message:
'Errors in the OLAP storage engine:
A duplicate attribute key has been found when processing:
Table: 'dbo_DimGeography',
Column: 'StateProvinceKey', Value: '23'.
The attribute is State-Province'."
You verify that the data is accurate.
You need to ensure that the dimension Processes successfully.
What should you do?
A. Delete the Geography hierarchy.
B. Relate the State-Province and Country attributes directly to the City attribute.
C. Remove the duplicate data from the DimGeography table.
D. Remove the State-Province attribute.
Answer: B
NEW QUESTION: 4
See the Exhibit and Examine the structure of the CUSTOMERS table:
Using the CUSTOMERS table, you need to generate a report that shows an increase in the credit limit by 15% for all customers. Customers whose credit limit has not been entered should have the message "Not Available" displayed.
Which SQL statement would produce the required result?
A. SELECT NVL(cust_credit_limit,'Not Available')*.15 "NEW CREDIT" FROM customers;
B. SELECT NVL(TO_CHAR(cust_credit_limit*.15),'Not Available') "NEW CREDIT" FROM customers;
C. SELECT NVL(cust_credit_limit*.15,'Not Available') "NEW CREDIT" FROM customers;
D. SELECT TO_CHAR(NVL(cust_credit_limit*.15,'Not Available')) "NEW CREDIT" FROM customers;
Answer: B
Explanation:
NVL Function
Converts a null value to an actual value:
Data types that can be used are date, character, and number.
Data types must match:
-
NVL(commission_pct,0)
-
NVL(hire_date,'01-JAN-97')
- NVL(job_id,'No Job Yet')