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NEW QUESTION: 1
While in the managerial training program for a large multinational corporation, Daniel Waite is assigned a one-year rotation in the Mediterranean. Upon arriving at the assignment, he purchases a local (foreign currency) bond with an annual coupon of 8.5 percent for 96.5. He holds the bond for one year and then sells it for 98.0. Waite is pleased with his return, which he calculates at 10.4%.
On the plane ride home, Waite is seated next to his fellow coworker, Penny King, who begins to talk about the depressed local economy and the negative returns she had experienced on her local bond investments over the same period as Waite. She states that her total dollar return on an 8.0 percent annual coupon bond purchased at the same time as Waite's for 95.0 and sold for 98.0 (at the same time as Waite's) was a disappointing negative 10.737%.
Assume that King's calculation is correct and that Waite made some calculation error. Which of the following is closest to Waite's actual total dollar return?
A. -10.363%.
B. -18.756%.
C. -32.435%.
D. -11.712%.
Answer: D
Explanation:
Explanation/Reference:
Explanation:
Waite forgot to take into account the impact of the percentage change in the dollar value of the foreign currency.
Using the information provided by King, we can calculate the percentage change in the value of the foreign currency and then calculate Waite's total dollar return. Using the formula for total dollar return of:
R$= { [ 1+($coupon + VEND- VBEG)/ VBEG] * (1 + g) } - 1,
-0.10737= { [ 1+(8.0 + 98.0 - 95.0)/95.0 ] * (1 + FChange) } - 1
-0.10737 = { [1.115789] * (1 + FChange) } - 1
-0.2000 = FChange, or 20.0% depreciation.
Now, we can calculate Waite's total dollar return.
R$ Waite= { [ 1+(8.5 + 98.0 - 96.5)/96.5 ] * (1 - 0.20) } - 1
R$ Waite= -11.712%

NEW QUESTION: 2
A developer writes an interceptor class and a stateless session bean: A client acquires an EJB reference to the FooLocal business interface and invokes the foo() method one time. Which describes the output?

A. Foo FooInt AInt
B. AInt Foo
C. FooInt AInt Foo
D. AInt FooInt Foo
Answer: D
Explanation:
* At the end of the chain of interceptors, the actual bean method gets called.
* Interceptors can be bound in three different ways:
Default Class level Method level
In this question both class level and method level interceptors are used.
The class level interceptor intercepts before the method-level interceptor.
Note:
*Interceptors are used in conjunction with Java EE managed classes to allow developers to invoke interceptor methods on an associated target class, in conjunction with method invocations or lifecycle events. Common uses of interceptors are logging, auditing, and profiling.
*An interceptor can be defined within a target class as an interceptor method, or in an associated class called an interceptor class. Interceptor classes contain methods that are invoked in conjunction with the methods or lifecycle events of the target class.
Interceptor classes and methods are defined using metadata annotations, or in the deployment descriptor of the application containing the interceptors and target classes.
*javax.interceptor.AroundInvoke
Designates the method as an interceptor method.
*The target class can have any number of interceptor classes associated with it. The order in
which the interceptor classes are invoked is determined by the order in which the interceptor
classes are defined in the javax.interceptor.Interceptors annotation.
Reference: Introduction to EJB3 Interceptors
Reference: The Java EE 6 Tutorial, Overview of Interceptors

NEW QUESTION: 3

A. 0.0.027
B. 0.0.0.255
C. 0.0.0.224
D. 0.0.0.31
Answer: D
Explanation:
Slash Netmask Wildcard Mask
/27 255.255.255.224 0.0.0.31
Further reading
Source: https://en.wikipedia.org/wiki/Wildcard_mask