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NEW QUESTION: 1
Electrical systems are the lifeblood of computer operations. The continued supply of clean, steady power is required to maintain the proper personnel environment as well as to sustain data operations. Which of the following is not an element that can threaten power systems?
A. Faulty Ground
B. UPS
C. Transient Noise
D. Brownouts
Answer: B
Explanation:
Explanation/Reference:
Explanation:
An uninterruptible power supply (UPS) helps to ensure the continued supply of clean, steady power; it does not threaten it.
An uninterruptible power supply (UPS) is an electrical apparatus that provides emergency power to a load when the input power source, typically mains power, fails. A UPS differs from an auxiliary or emergency power system or standby generator in that it will provide near-instantaneous protection from input power interruptions, by supplying energy stored in batteries, supercapacitors, or flywheels. The on-battery runtime of most uninterruptible power sources is relatively short (only a few minutes) but sufficient to start a standby power source or properly shut down the protected equipment.
Incorrect Answers:
A: Transient Noise is an element that can threaten power systems. Therefore, this answer is incorrect.
B: Faulty Ground is an element that can threaten power systems. Therefore, this answer is incorrect.
C: A brownout is a prolonged period of lower than expected voltage; this an element that can threaten power systems. Therefore, this answer is incorrect.
References:
https://en.wikipedia.org/wiki/Uninterruptible_power_supply
NEW QUESTION: 2
ハニーポットIPSの目的は何ですか？
A. カスタマイズされたポリシーを作成する
B. 未知の攻撃を検出する
C. ストリームを正規化する
D. 攻撃に関する情報を収集する
Answer: D
Explanation:
Honeypot systems use a dummy server to attract attacks. The purpose of the honeypot approach is to distract attacks away from real network devices. By staging different types of vulnerabilities in the honeypot server, you can analyze incoming types of attacks and malicious traffic patterns.
Source: http://www.ciscopress.com/articles/article.asp?p=1336425
NEW QUESTION: 3
Given:
11.
String test = "a1b2c3";
12.
String[] tokens = test.split("\\d");
13.
for(String s: tokens) System.out.print(s + " ");
What is the result?
A. Compilation fails.
B. a1 b2 c3
C. a1b2c3
D. The code runs with no output.
E. a b c
F. 1 2 3
G. An exception is thrown at runtime.
Answer: E