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NEW QUESTION: 1
Note: This question is part of a series of questions that use the same scenario. For your convenience, the scenario is repeated in each question. Each question presents a different goal and answer choices, but the next of the scenario is exactly the same in each question in this series.
Start of repeated scenario
Contoso, Ltd. has Microsoft SQL Server databases that support a custom application. The current SQL Server environment consists of two servers: ContosoSQL1 and ContosoSQL2. These two servers participate in an Always On Availability Group named ContosoAG1 that is configured to use synchronous-commit with automatic failover. The secondary replica is not configured for read-only access.
The application performs both transactional processing and historical data retrieval in a database named ContosoDB. The application includes an inventory management module. The inventory management module and database have experienced performance issues.
Users report that a query named InventoryQuery1 takes a long time to complete. The query is shown as follows:
SELECT ProductNumber, Name, ProductLine
FROM Production.Product
WHERE ProductNumber = N'<specific product>'
The query plan used by SQL Server for this query is shown in the exhibit. (Click the Exhibit tab.) Various performance issues, including frequent long-term blocking episodes, prevent business users from completing their daily tasks. You suspect the database resources could be responsible. You must create Blocking reports for the ContosoDB database to identify issues.
Exhibit.
You plan to use Extended Events to review all Transact-SQL statements that are run against the ContosoSQL1 instance. The output from the Extended Events session must contain both start and stop events and must be written to a file. You must configure the Extended Events session to minimize possible data loss and reduce the effect on server performance.
You plan to deploy an additional secondary replica named ContosoSQL3 to ContosoAG1. Read-only traffic must be load-balanced between the two secondary replicas, regardless of which instance is the primary replica.
Contoso plans to add an additional dedicated reporting system that will rely on real-time data from the transactional databases.
End of repeated scenario
You need to troubleshoot and resolve the issue with InventoryQuery1.
Use the drop-down menus to select the answer choice that answers each question based on the information presented in the graphic.
Answer:
Explanation:
Explanation
Box 1: Key Lookup (clustered)
They Key Lookup (clustered) should be less than 50%.
Box 2: Change the table's primary key to the Product.ProductNumber column.
Incorrect: Non-Clustered Index Seek
Non-Clustered Index Seek occurs when Columns part of non-clustered index accessed in query and rows located in the B+ tree.
It is good and ideal to have a Non-Clustered Index Seek.
Action: Evaluate other operators
References:
https://www.sqlshack.com/sql-server-query-execution-plans-beginners-non-clustered-index-operators/
NEW QUESTION: 2
Windows Server 2016을 실행하는 Server1이라는 서버가 있습니다. Server1에는 Windows 응용 프로그램 프록시 역할 서비스가 설치되어 있습니다. RD 게이트웨이 (원격 데스크톱 게이트웨이) 서비스를 배포 할 계획입니다. 클라이언트는 Windows, iOS 및 Android 장치를 포함한 다양한 유형의 장치를 사용하여 RD 게이트웨이 서비스에 연결합니다.
웹 응용 프로그램 프록시를 통해 RD 게이트웨이 서비스를 게시해야 합니다.
어떤 명령을 실행해야 합니까? 답변하려면 답변 영역에서 적절한 옵션을 선택하십시오.
Answer:
Explanation:
설명
NEW QUESTION: 3
What technology is necessary to support vPC+?
A. RPVST
B. OTV
C. MPLS
D. MST
E. vCenter
F. FabricPath
Answer: F
NEW QUESTION: 4
The SAS data set ONE consists of five million observations and has 25 variables. Which one of the following SAS programs successfully creates three new variables TOTREV, TOTCOST, and PROFIT and requires the least CPU time to be processed?
A. data two;
set one;
totrev = sum(price * quantity);
totcost = sum(fixed,variable);
profit = sum(totrev,otcost);
if totrev > 1000;
run;
B. data two;
set one;
totrev = sum(price * quantity);
if totrev > 1000;
totcost = sum(fixed,variable);
profit = sum(totrev,otcost);
run;
C. data two;
set one;
where totrev > 1000;
totrev = sum(price * quantity);
totcost = sum(fixed,variable);
profit = sum(totrev,otcost);
run;
D. data two;
set one;
totrev = sum(price * quantity);
where totrev > 1000;
totcost = sum(fixed,variable);
profit = sum(totrev,otcost);
run;
Answer: B