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NEW QUESTION: 1
In what situation must spanning-tree be implemented?
A. when first hop redundancy protocol exists with redundant Layer 2 links between distribution switches
B. when it is necessary to speed up network convergence in case of link failure
C. when a VLAN spans access layer switches to support business applications
D. when trunks need to extend multiple VLANs across access switches
Answer: A

NEW QUESTION: 2
Under which configuration hierarchy is an access profile configured for firewall user authentication?
A. [edit firewall-authentication]
B. [edit access]
C. [edit security access]
D. [edit firewall access]
Answer: B

NEW QUESTION: 3
Click on the exhibit button below.

Which of the following is the correct configuration for an MP-BGP session on 6VPE1?
A. PE1>config>router>bgp#info
--------------------------------------------
group "multi-bgp"
family ipv6 vpn-ipv6
neighbor 10.10.10.2/32
local-address 10.10.10.1
peer-as 64496
exit
exit
B. PE1>config>router>bgp#info
--------------------------------------------
group "multi-bgp"
family vpn-ipv6
neighbor 10.10.10.2/32
local-address 10.10.10.1
peer-as 64496
exit
exit
C. PE1>config>router>bgp#info
-------------------------------------------
group "multi-bgp"
family ipv6 vpn-ipv4
neighbor 10.10.10.2
local-address 10.10.10.1
peer-as 64496
exit
exit
D. PE1>config>router>bgp#info
--------------------------------------------
group "multi-bgp"
family vpn-ipv6
neighbor 10.10.10 2
local-address 10.10.10.1
peer-as 64496
exit
exit
Answer: D

NEW QUESTION: 4
Which two blocks of code execute successfully?
A. DECLARE
TYPE tab_type IS TABLE OF NUMBER;
my_tab tab_type;
BEGIN
my_tab. EXTEND (2);
my_tab (1) := 55;
END;
B. DECLARE
TYPE tab_type IS TABLE OF NUMBER;
my_tab tab_type;
BEGIN
my_tab (1) :=1;
END;
C. DECLARE
TYPE tab_type IS TABLE OF NUMBER;
my_tab tab_type;
BEGIN
my_tab := tab_type ();
my_tab (1) := 55;
END;
D. DECLARE
TYPE tab_type IS TABLE OF NUMBER;
my_tab tab_type := tab_type(2);
BEGIN
my_tab(1) :=55;
END;
E. DECLARE
TYPE tab_type IS TABLE OF NUMBER
my_tab tab_type := tab_type (2, NULL, 50);
BEGIN
my_tab.EXTEND (3, 2);
END;
Answer: C,D