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NEW QUESTION: 1
Solutions Architectは、Amazon EC2インスタンスで実行されているウェブアプリケーションのグループのために集中ログソリューションを設計する必要があります。このソリューションは、予算上の制約から最小限の開発努力で済みます。
建築家は次のうちどれをお勧めしますか？
A. AWSマネジメントコンソールでAmazon CloudWatchイベントを有効にする
B. 各インスタンスにcorntabジョブスクリプトを作成して、ログをAmazon S3に定期的にプッシュします。
C. AWS CloudTrailがアプリケーションによって呼び出されたすべてのAPI呼び出しをマッピングできるようにします。
D. Amazon CloudWatch LogsエージェントをAmazon EC2にインストールして設定します
Answer: D

NEW QUESTION: 2
A network technician wants to gain a better understanding of network trends to determine if they are over capacity. Which of the following processes should the technician use?
A. Traffic analysis
B. Vulnerability scanning
C. Port scanning
D. Log review
Answer: A

NEW QUESTION: 3
Move the entire Trees worksheet from this workbook into the Contracts workbook, so that it is the first worksheet in the workbook.

A. Option A
Right click on the trees worksheet -> select move or copy -> select Contracts workbook -> ok
Answer: A

NEW QUESTION: 4
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects.
You need to retrieve the students who scored the highest marks for each subject along with the marks.
Which Transact-SQL query should you use?
A. SELECT StudentCode AS Code, Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
B. SELECT StudentCode AS Code, Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
C. SELECT StudentCode as Code, DENSE_RANK() OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
D. SELECT StudentCode as Code, NTILE(2) OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
E. SELECT StudentCode AS Code, Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANXO OVER(PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
F. SELECT StudentCode AS Code, Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
G. SELECT StudentCode as Code, RANK() OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
H. SELECT Id, Name, Marks, DENSE_RANK() OVER(ORDER BY Marks DESC) AS Rank FROM StudentMarks
Answer: B
Explanation:
Explanation/Reference:
Explanation: