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NEW QUESTION: 1
Ihr Netzwerk enthält eine Active Directory-Domäne mit dem Namen contoso.com. Die Domäne enthält zwei Server mit den Namen Server1 und Server2, auf denen Windows Server 2016 ausgeführt wird.
Auf Server1 ist IP-Adressverwaltung (IPAM) installiert. Auf Server2 ist die DHCP-Serverrolle installiert. Der IPAM-Server ruft Daten von Server2 ab.
Sie erstellen ein Domänenbenutzerkonto mit dem Namen Benutzer1.
Sie müssen sicherstellen, dass Benutzer1 IPAM zum Verwalten von DHCP verwenden kann.
Welchen Befehl sollten Sie auf Server1 ausführen? Wählen Sie zum Beantworten die entsprechenden Optionen im Antwortbereich aus.

Answer:
Explanation:


NEW QUESTION: 2
File Integrity Monitoring (FIM) is considered a
A. Network based security preventative control
B. User segmentation control
C. Security detective control
D. Software segmentation control
Answer: C

NEW QUESTION: 3
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the following requirements are met:
Students must be ranked based on their average marks.

If one or more students have the same average, the same rank must be given to these students.

Consecutive ranks must be skipped when the same rank is assigned.

Which Transact-SQL query should you use?
A. SELECT StudentCode as Code,
NTILE(2) OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
B. SELECT StudentCode as Code,
DENSE_RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
C. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
D. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER(PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
E. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
F. SELECT Id, Name, Marks,
DENSE_RANK() OVER(ORDER BY Marks DESC) AS Rank
FROM StudentMarks
G. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
H. SELECT StudentCode as Code,
RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
Answer: H
Explanation:
Explanation/Reference:
Reference: http://msdn.microsoft.com/en-us/library/ms189798.aspx