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NEW QUESTION: 1
このクラスを考えると：

And given this main method, located in another class:

行n1に独立して挿入された場合、どの3行がプログラムに0の残高を印刷させますか？
A. acct.changeAmount(-acct.amount); <option G earlier>
B. acct.setAmount(0);
C. acct.changeAmount(0); <option F earlier>
D. acct.setAmount(-acct.getAmount());
E. acct.getAmount() = 0; <option E earlier>
F. this.amount = 0; <option A earlier>
G. acct.amount = 0; <option D earlier>
Answer: C,E,G

NEW QUESTION: 2
Which two statements about Net Flow version g are true? (Choose two)
A. It supports both encryption and authentication
B. It up to six exporters per cache
C. It supports export over TCP and UDP
D. It supports up to two exporters per cache
E. Each flow monitor supports up to 10 exporters
F. It supports export over UDP only
Answer: C,E

NEW QUESTION: 3
You are developing a mobile app to manage meetups. The app allows for users to view the 25 closest people with similar interests. You have a table that contains records for approximately two million people.
You create the table by running the following Transact-SQL statement:

You create the following table valued function to generate lists of people:

You need to build a report that shows meetings with at least two people only.
What should you use?
A. PIVOT
B. CROSS APPLY
C. LEFT OUTER JOIN
D. OUTER APPLY
Answer: B
Explanation:
Explanation/Reference:
References: https://www.sqlshack.com/the-difference-between-cross-apply-and-outer-apply-in-sql-server/

NEW QUESTION: 4
Refer to the exhibit.
A network administrator needs to configure a dynamic wireless mesh to connect HP MSM
AP 1 to the network.
AP 1 will be installed outdoors where Ethernet is not available. It will connect to AP2ortoAP3; one of which will provide the primary link and one of which will act as backup. Both AP 2 and AP 3 have connections to the Ethernet network and should not connect to each other.
What are appropriate roles for the three APs?
A. 1 = Slave; 2 = Master; 3 = Master
B. 1 = Slave; 2 = Master 3 = Alternate master
C. 1 = Alternate master; 2 = Alternate master; 3 = Alternate master
D. 1 = Slave; 2 = Alternate master; 3 = Alternate master
Answer: B