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NEW QUESTION: 1
Which two statements correctly describe steps in the OSI data encapsulation process? (Choose two.)
A. The transport layer divides a data stream into segments and may add reliability and flow control information.
B. Packets are created when the network layer adds Layer 3 addresses and control information to a segment.
C. Packets are created when the network layer encapsulates a frame with source and destination host addresses and protocol-related control information.
D. The data link layer adds physical source and destination addresses and an FCS to the segment.
E. The presentation layer translates bits into voltages for transmission across the physical link.
Answer: A,B
Explanation:
Explanation/Reference:
Explanation:
The Application Layer (Layer 7) refers to communications services to applications and is the interface between the network and the application. Examples include. Telnet, HTTP, FTP, Internet browsers, NFS, SMTP gateways, SNMP, X.400 mail, and FTAM. The Presentation Layer (Layer 6) defining data formats, such as ASCII text, EBCDIC text, binary, BCD, and JPEG. Encryption also is defined as a presentation layer service. Examples include. JPEG, ASCII, EBCDIC, TIFF, GIF, PICT, encryption, MPEG, and MIDI.
The Session Layer (Layer 5) defines how to start, control, and end communication sessions. This includes the control and management of multiple bidirectional messages so that the application can be notified if only some of a series of messages are completed. This allows the presentation layer to have a seamless view of an incoming stream of data. The presentation layer can be presented with data if all flows occur in some cases. Examples include. RPC, SQL, NFS, NetBios names, AppleTalk ASP, and DECnet SCP The Transport Layer (Layer 4) defines several functions, including the choice of protocols. The most important Layer 4 functions are error recovery and flow control. The transport layer may provide for retransmission, i.e., error recovery, and may use flow control to prevent unnecessary congestion by attempting to send data at a rate that the network can accommodate, or it might not, depending on the choice of protocols. Multiplexing of incoming data for different flows to applications on the same host is also performed. Reordering of the incoming data stream when packets arrive out of order is included.
Examples include. TCP, UDP, and SPX. The Network Layer (Layer 3) defines end-to-end delivery of packets and defines logical addressing to accomplish this. It also defines how routing works and how routes are learned; and how to fragment a packet into smaller packets to accommodate media with smaller maximum transmission unit sizes. Examples include. IP, IPX, AppleTalk DDP, and ICMP. Both IP and IPX define logical addressing, routing, the learning of routing information, and end-to-end delivery rules. The IP and IPX protocols most closely match the OSI network layer (Layer 3) and are called Layer 3 protocols because their functions most closely match OSI's Layer 3. The Data Link Layer (Layer 2) is concerned with getting data across one particular link or medium.
The data link protocols define delivery across an individual link. These protocols are necessarily concerned with the type of media in use. Examples include. IEEE 802.3/802.2, HDLC, Frame Relay, PPP, FDDI, ATM, and IEEE 802.5/802.2.

NEW QUESTION: 2
Insert a Tasks Web Part inthe default location of the current page Minimize the Tasks Web Part.

Answer:
Explanation:
Check the explanation below.
Explanation
Explanation answer below




NEW QUESTION: 3
Scenario
Refer to the topology. Your company has connected the routers R1. R2. and R3 with serial
links. R2 and R3 are connected to the switches SW1 and SW2, respectively. SW1 and
SW2 are also connected to the routers R4 and R5.
The EIGRP routing protocol is configured.
You are required to troubleshoot and resolve the EIGRP issues between the various
routers.
Use the appropriate show commands to troubleshoot the issues.






The loopback interfaces on R4 with the IP addresses of 10.4.4.4 /32, 10.4.4.5/32. and 10.4.4.6/32 are not appearing in the routing table of R5 Why are the interfaces missing?
A. The interfaces are shutdown, so they are not being advertised.
B. Automatic summarization is enabled, so only the 10.0.0.0 network is displayed.
C. R4 has been incorrectly configured to be in another AS, so it does not peer with R5.
D. The loopback addresses haven't been advertised, and the network command is missing on R4.
Answer: C
Explanation:
For an EIGRP neighbor to form, the following must match:
-Neighbors must be in the same subnet- K values- AS numbers- Authentication method and key strings
Here, we see that R4 is configured for EIGRP AS 2, when it should be AS 1.